P
Patrick
I am using Access 2000 and am trying to a File Open Dialogue running....and
getting compile error "Method not found". I have added a library reference
for "Microsoft Office 11.0 object Library". If I type "Application.",
Intellisense does not show FIleDialogue as a Method. (Is it possible I might
be better off using the Windows SDK equivalent? HOw do I find out more about
that?)
The code I am using to start with is a well known starting point but will
not compile. I suspect it might not work with Access 2000......
Private Sub cmdOpenDialogue_DblClick(Cancel As Integer)
'Declare a variable as a FileDialog object.
Dim fd As Office.FileDialog
Dim app As Application
'Create a FileDialog object as a File Picker dialog box.
Set fd = Application.FileDialog(msoFileDialogFilePicker)
'Declare a variable to contain the path
'of each selected item. Even though the path is a String,
'the variable must be a Variant because For Each...Next
'routines only work with Variants and Objects.
Dim vrtSelectedItem As Variant
'Use a With...End With block to reference the FileDialog object.
With fd
'Use the Show method to display the File Picker dialog box
'The user pressed the action button.
If .Show = -1 Then
'Step through the FileDialogSelectedItems collection.
For Each vrtSelectedItem In .SelectedItems
'vrtSelectedItem contains the path of each selected item.
'Here use any file I/O functions you want on the path.
'This example simply displays the path in a message box.
MsgBox "The path is: " & vrtSelectedItem
Next vrtSelectedItem
'The user pressed Cancel.
Else
End If
End With
'Set the object variable to Nothing.
Set fd = Nothing
End Sub
getting compile error "Method not found". I have added a library reference
for "Microsoft Office 11.0 object Library". If I type "Application.",
Intellisense does not show FIleDialogue as a Method. (Is it possible I might
be better off using the Windows SDK equivalent? HOw do I find out more about
that?)
The code I am using to start with is a well known starting point but will
not compile. I suspect it might not work with Access 2000......
Private Sub cmdOpenDialogue_DblClick(Cancel As Integer)
'Declare a variable as a FileDialog object.
Dim fd As Office.FileDialog
Dim app As Application
'Create a FileDialog object as a File Picker dialog box.
Set fd = Application.FileDialog(msoFileDialogFilePicker)
'Declare a variable to contain the path
'of each selected item. Even though the path is a String,
'the variable must be a Variant because For Each...Next
'routines only work with Variants and Objects.
Dim vrtSelectedItem As Variant
'Use a With...End With block to reference the FileDialog object.
With fd
'Use the Show method to display the File Picker dialog box
'The user pressed the action button.
If .Show = -1 Then
'Step through the FileDialogSelectedItems collection.
For Each vrtSelectedItem In .SelectedItems
'vrtSelectedItem contains the path of each selected item.
'Here use any file I/O functions you want on the path.
'This example simply displays the path in a message box.
MsgBox "The path is: " & vrtSelectedItem
Next vrtSelectedItem
'The user pressed Cancel.
Else
End If
End With
'Set the object variable to Nothing.
Set fd = Nothing
End Sub