Access bug?

R

Ronald

Hi all.

This code:

Private Sub cboNamen_AfterUpdate()

Dim intRowCount As Integer
Dim dblLicenceFee As Double
Dim intSelectCount As Integer

dblLicenceFee = 0#
intSelectCount = 0

For intRowCount = 0 To Me![cboNamen].Recordset.RecordCount - 1
If (Me![cboNamen].Selected(intRowCount) = True) Then
dblLicenceFee = dblLicenceFee + CDbl(Me![cboNamen].Column(2,
intRowCount))
intSelectCount = intSelectCount + 1
End If
Next intRowCount

If (intSelectCount = 0) Then
MsgBox "No licence selected!", vbInformation
Else
Me![txtAvgLicence] = dblLicenceFee / intSelectCount
End If

End Sub

I put in the event you can see of a multi selectable combobox (Access 2007).
The code is OK, all records are filled, but in certain specific
circumstances (I know exactly when) I get an ‘Invalid use of Null’ error in
the line that adds the LicenceFee. But when I go to error correction and
press F5, the code continues and completes without any error.
I tried requerying the control, build in a loop (in case of a timing issue),
using other events, but I cannot get it fixed.
I feel it might be a bug in Access. I have created a specific database to
check the behavior. How can I get it to someone to confirm the behavior and
maybe get it to Microsoft?

Thanks,

Ronald.
 
D

Douglas J. Steele

The code's ok, but it could be better:

Private Sub cboNamen_AfterUpdate()

Dim dblLicenceFee As Double
Dim varSelected As Variant

dblLicenceFee = 0#

With Me![cboNamen]
If .ItemsSelected.Count = 0 Then
MsgBox "No licence selected!", vbInformation
Else
For Each varSelected In .ItemsSelected
dblLicenceFee = dblLicenceFee + CDbl(Nz(.Column(2, varSelected), 0))
Next varSelected
Me![txtAvgLicence] = dblLicenceFee / .ItemsSelected.Count
End If
End With
1
End Sub
 
R

Ronald

There are no Null values in the table!
When I print the value of the control in immediate mode, it is displayed.
And, like I said, when I press F5 the code continues without an error.

ryguy7272 said:
Those Nulls can be tricky to deal with. Can you wrap your problematic Fields
with NZ()? Also, take a look at this:
http://articles.techrepublic.com.com/5100-10878_11-6125114.html

--
Ryan---
If this information was helpful, please indicate this by clicking ''Yes''.


Ronald said:
Hi all.

This code:

Private Sub cboNamen_AfterUpdate()

Dim intRowCount As Integer
Dim dblLicenceFee As Double
Dim intSelectCount As Integer

dblLicenceFee = 0#
intSelectCount = 0

For intRowCount = 0 To Me![cboNamen].Recordset.RecordCount - 1
If (Me![cboNamen].Selected(intRowCount) = True) Then
dblLicenceFee = dblLicenceFee + CDbl(Me![cboNamen].Column(2,
intRowCount))
intSelectCount = intSelectCount + 1
End If
Next intRowCount

If (intSelectCount = 0) Then
MsgBox "No licence selected!", vbInformation
Else
Me![txtAvgLicence] = dblLicenceFee / intSelectCount
End If

End Sub

I put in the event you can see of a multi selectable combobox (Access 2007).
The code is OK, all records are filled, but in certain specific
circumstances (I know exactly when) I get an ‘Invalid use of Null’ error in
the line that adds the LicenceFee. But when I go to error correction and
press F5, the code continues and completes without any error.
I tried requerying the control, build in a loop (in case of a timing issue),
using other events, but I cannot get it fixed.
I feel it might be a bug in Access. I have created a specific database to
check the behavior. How can I get it to someone to confirm the behavior and
maybe get it to Microsoft?

Thanks,

Ronald.
 
R

Ronald

Hi Douglas.

Thanks for your code! Any enhancements are always appreciated!
But it does not function correctly, the result is always 0.
In immediate mode the .ItemsSelected.Count does display the correct number
of items selected. But after the For Each line is processed the code
immediately goes to the ‘Me![txtAvgLicence] = dblLicenceFee /
..ItemsSelected.Count’ line, so no average is calculated.

Also my initial question still stands. Why do I get an ‘Invalid use of Null’
error while the table does not contain any empty fields? You use the Nz
function to trap the error but then you only get a wrong answer and don’t get
an indication anything is wrong.
Why when I press F5 (or F8) after the ‘Invalid use of Null’ error occurs,
code continues without any error! If there really is a Null value the error
should reappear!
I have a database dedicated to this error to prove it.

Any additional help or suggestion is very welcome.

Ronald.


Douglas J. Steele said:
The code's ok, but it could be better:

Private Sub cboNamen_AfterUpdate()

Dim dblLicenceFee As Double
Dim varSelected As Variant

dblLicenceFee = 0#

With Me![cboNamen]
If .ItemsSelected.Count = 0 Then
MsgBox "No licence selected!", vbInformation
Else
For Each varSelected In .ItemsSelected
dblLicenceFee = dblLicenceFee + CDbl(Nz(.Column(2, varSelected), 0))
Next varSelected
Me![txtAvgLicence] = dblLicenceFee / .ItemsSelected.Count
End If
End With
1
End Sub


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Ronald said:
Hi all.

This code:

Private Sub cboNamen_AfterUpdate()

Dim intRowCount As Integer
Dim dblLicenceFee As Double
Dim intSelectCount As Integer

dblLicenceFee = 0#
intSelectCount = 0

For intRowCount = 0 To Me![cboNamen].Recordset.RecordCount - 1
If (Me![cboNamen].Selected(intRowCount) = True) Then
dblLicenceFee = dblLicenceFee + CDbl(Me![cboNamen].Column(2,
intRowCount))
intSelectCount = intSelectCount + 1
End If
Next intRowCount

If (intSelectCount = 0) Then
MsgBox "No licence selected!", vbInformation
Else
Me![txtAvgLicence] = dblLicenceFee / intSelectCount
End If

End Sub

I put in the event you can see of a multi selectable combobox (Access
2007).
The code is OK, all records are filled, but in certain specific
circumstances (I know exactly when) I get an 'Invalid use of Null' error
in
the line that adds the LicenceFee. But when I go to error correction and
press F5, the code continues and completes without any error.
I tried requerying the control, build in a loop (in case of a timing
issue),
using other events, but I cannot get it fixed.
I feel it might be a bug in Access. I have created a specific database to
check the behavior. How can I get it to someone to confirm the behavior
and
maybe get it to Microsoft?

Thanks,

Ronald.


.
 
D

Douglas J. Steele

Not sure what you mean by "no average is calculated"

Are you sure that the value you need to be averaging is the third column of
your list box? (remember that the Column collection starts numbering at 0)

Are you sure that you've got the ColumnCount property of the list box set to
at least 3?

Are you sure you've got all of the periods in there correctly? Without the
With structure, the code would be

Private Sub cboNamen_AfterUpdate()

Dim dblLicenceFee As Double
Dim varSelected As Variant

dblLicenceFee = 0#

If Me![cboNamen].ItemsSelected.Count = 0 Then
MsgBox "No licence selected!", vbInformation
Else
For Each varSelected In Me![cboNamen].ItemsSelected
dblLicenceFee = dblLicenceFee + _
CDbl(Nz(Me![cboNamen].Column(2, varSelected), 0))
Next varSelected
Me![txtAvgLicence] = _
dblLicenceFee / Me![cboNamen].ItemsSelected.Count
End If

End Sub


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Ronald said:
Hi Douglas.

Thanks for your code! Any enhancements are always appreciated!
But it does not function correctly, the result is always 0.
In immediate mode the .ItemsSelected.Count does display the correct number
of items selected. But after the For Each line is processed the code
immediately goes to the 'Me![txtAvgLicence] = dblLicenceFee /
.ItemsSelected.Count' line, so no average is calculated.

Also my initial question still stands. Why do I get an 'Invalid use of
Null'
error while the table does not contain any empty fields? You use the Nz
function to trap the error but then you only get a wrong answer and don't
get
an indication anything is wrong.
Why when I press F5 (or F8) after the 'Invalid use of Null' error occurs,
code continues without any error! If there really is a Null value the
error
should reappear!
I have a database dedicated to this error to prove it.

Any additional help or suggestion is very welcome.

Ronald.


Douglas J. Steele said:
The code's ok, but it could be better:

Private Sub cboNamen_AfterUpdate()

Dim dblLicenceFee As Double
Dim varSelected As Variant

dblLicenceFee = 0#

With Me![cboNamen]
If .ItemsSelected.Count = 0 Then
MsgBox "No licence selected!", vbInformation
Else
For Each varSelected In .ItemsSelected
dblLicenceFee = dblLicenceFee + CDbl(Nz(.Column(2, varSelected),
0))
Next varSelected
Me![txtAvgLicence] = dblLicenceFee / .ItemsSelected.Count
End If
End With
1
End Sub


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Ronald said:
Hi all.

This code:

Private Sub cboNamen_AfterUpdate()

Dim intRowCount As Integer
Dim dblLicenceFee As Double
Dim intSelectCount As Integer

dblLicenceFee = 0#
intSelectCount = 0

For intRowCount = 0 To Me![cboNamen].Recordset.RecordCount - 1
If (Me![cboNamen].Selected(intRowCount) = True) Then
dblLicenceFee = dblLicenceFee + CDbl(Me![cboNamen].Column(2,
intRowCount))
intSelectCount = intSelectCount + 1
End If
Next intRowCount

If (intSelectCount = 0) Then
MsgBox "No licence selected!", vbInformation
Else
Me![txtAvgLicence] = dblLicenceFee / intSelectCount
End If

End Sub

I put in the event you can see of a multi selectable combobox (Access
2007).
The code is OK, all records are filled, but in certain specific
circumstances (I know exactly when) I get an 'Invalid use of Null'
error
in
the line that adds the LicenceFee. But when I go to error correction
and
press F5, the code continues and completes without any error.
I tried requerying the control, build in a loop (in case of a timing
issue),
using other events, but I cannot get it fixed.
I feel it might be a bug in Access. I have created a specific database
to
check the behavior. How can I get it to someone to confirm the behavior
and
maybe get it to Microsoft?

Thanks,

Ronald.


.
 
R

Ronald

I meant that the addition is not performed because the code immediately jumps
from the 'For Each ...' line to the 'Me![txtAvgLicence] = ...' line. So the
result always is 0.

I'm very sure column 2 is the right column. I checked it in immediate mode.
Column 0 is the checkbox of the multi select combobox and column 1 is the
name of the licencee.

The table in the rowsource of the combobox contains 5 records.

I also tried:
Dim ctlControl as ComboBox

Set ctlCombobox = Me![cboNamen]
With [ctlCombobox]
and so on but it makes no difference.

Douglas J. Steele said:
Not sure what you mean by "no average is calculated"

Are you sure that the value you need to be averaging is the third column of
your list box? (remember that the Column collection starts numbering at 0)

Are you sure that you've got the ColumnCount property of the list box set to
at least 3?

Are you sure you've got all of the periods in there correctly? Without the
With structure, the code would be

Private Sub cboNamen_AfterUpdate()

Dim dblLicenceFee As Double
Dim varSelected As Variant

dblLicenceFee = 0#

If Me![cboNamen].ItemsSelected.Count = 0 Then
MsgBox "No licence selected!", vbInformation
Else
For Each varSelected In Me![cboNamen].ItemsSelected
dblLicenceFee = dblLicenceFee + _
CDbl(Nz(Me![cboNamen].Column(2, varSelected), 0))
Next varSelected
Me![txtAvgLicence] = _
dblLicenceFee / Me![cboNamen].ItemsSelected.Count
End If

End Sub


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Ronald said:
Hi Douglas.

Thanks for your code! Any enhancements are always appreciated!
But it does not function correctly, the result is always 0.
In immediate mode the .ItemsSelected.Count does display the correct number
of items selected. But after the For Each line is processed the code
immediately goes to the 'Me![txtAvgLicence] = dblLicenceFee /
.ItemsSelected.Count' line, so no average is calculated.

Also my initial question still stands. Why do I get an 'Invalid use of
Null'
error while the table does not contain any empty fields? You use the Nz
function to trap the error but then you only get a wrong answer and don't
get
an indication anything is wrong.
Why when I press F5 (or F8) after the 'Invalid use of Null' error occurs,
code continues without any error! If there really is a Null value the
error
should reappear!
I have a database dedicated to this error to prove it.

Any additional help or suggestion is very welcome.

Ronald.


Douglas J. Steele said:
The code's ok, but it could be better:

Private Sub cboNamen_AfterUpdate()

Dim dblLicenceFee As Double
Dim varSelected As Variant

dblLicenceFee = 0#

With Me![cboNamen]
If .ItemsSelected.Count = 0 Then
MsgBox "No licence selected!", vbInformation
Else
For Each varSelected In .ItemsSelected
dblLicenceFee = dblLicenceFee + CDbl(Nz(.Column(2, varSelected),
0))
Next varSelected
Me![txtAvgLicence] = dblLicenceFee / .ItemsSelected.Count
End If
End With
1
End Sub


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Hi all.

This code:

Private Sub cboNamen_AfterUpdate()

Dim intRowCount As Integer
Dim dblLicenceFee As Double
Dim intSelectCount As Integer

dblLicenceFee = 0#
intSelectCount = 0

For intRowCount = 0 To Me![cboNamen].Recordset.RecordCount - 1
If (Me![cboNamen].Selected(intRowCount) = True) Then
dblLicenceFee = dblLicenceFee + CDbl(Me![cboNamen].Column(2,
intRowCount))
intSelectCount = intSelectCount + 1
End If
Next intRowCount

If (intSelectCount = 0) Then
MsgBox "No licence selected!", vbInformation
Else
Me![txtAvgLicence] = dblLicenceFee / intSelectCount
End If

End Sub

I put in the event you can see of a multi selectable combobox (Access
2007).
The code is OK, all records are filled, but in certain specific
circumstances (I know exactly when) I get an 'Invalid use of Null'
error
in
the line that adds the LicenceFee. But when I go to error correction
and
press F5, the code continues and completes without any error.
I tried requerying the control, build in a loop (in case of a timing
issue),
using other events, but I cannot get it fixed.
I feel it might be a bug in Access. I have created a specific database
to
check the behavior. How can I get it to someone to confirm the behavior
and
maybe get it to Microsoft?

Thanks,

Ronald.



.


.
 
D

Douglas J. Steele

Just to be certain. You're calling this "a multi selectable combobox", but
there's no such thing. Combo boxes do not have a MultiSelect property: only
list boxes do. Is this a combo box?


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Ronald said:
I meant that the addition is not performed because the code immediately
jumps
from the 'For Each ...' line to the 'Me![txtAvgLicence] = ...' line. So
the
result always is 0.

I'm very sure column 2 is the right column. I checked it in immediate
mode.
Column 0 is the checkbox of the multi select combobox and column 1 is the
name of the licencee.

The table in the rowsource of the combobox contains 5 records.

I also tried:
Dim ctlControl as ComboBox

Set ctlCombobox = Me![cboNamen]
With [ctlCombobox]
and so on but it makes no difference.

Douglas J. Steele said:
Not sure what you mean by "no average is calculated"

Are you sure that the value you need to be averaging is the third column
of
your list box? (remember that the Column collection starts numbering at
0)

Are you sure that you've got the ColumnCount property of the list box set
to
at least 3?

Are you sure you've got all of the periods in there correctly? Without
the
With structure, the code would be

Private Sub cboNamen_AfterUpdate()

Dim dblLicenceFee As Double
Dim varSelected As Variant

dblLicenceFee = 0#

If Me![cboNamen].ItemsSelected.Count = 0 Then
MsgBox "No licence selected!", vbInformation
Else
For Each varSelected In Me![cboNamen].ItemsSelected
dblLicenceFee = dblLicenceFee + _
CDbl(Nz(Me![cboNamen].Column(2, varSelected), 0))
Next varSelected
Me![txtAvgLicence] = _
dblLicenceFee / Me![cboNamen].ItemsSelected.Count
End If

End Sub


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Ronald said:
Hi Douglas.

Thanks for your code! Any enhancements are always appreciated!
But it does not function correctly, the result is always 0.
In immediate mode the .ItemsSelected.Count does display the correct
number
of items selected. But after the For Each line is processed the code
immediately goes to the 'Me![txtAvgLicence] = dblLicenceFee /
.ItemsSelected.Count' line, so no average is calculated.

Also my initial question still stands. Why do I get an 'Invalid use of
Null'
error while the table does not contain any empty fields? You use the Nz
function to trap the error but then you only get a wrong answer and
don't
get
an indication anything is wrong.
Why when I press F5 (or F8) after the 'Invalid use of Null' error
occurs,
code continues without any error! If there really is a Null value the
error
should reappear!
I have a database dedicated to this error to prove it.

Any additional help or suggestion is very welcome.

Ronald.


:

The code's ok, but it could be better:

Private Sub cboNamen_AfterUpdate()

Dim dblLicenceFee As Double
Dim varSelected As Variant

dblLicenceFee = 0#

With Me![cboNamen]
If .ItemsSelected.Count = 0 Then
MsgBox "No licence selected!", vbInformation
Else
For Each varSelected In .ItemsSelected
dblLicenceFee = dblLicenceFee + CDbl(Nz(.Column(2,
varSelected),
0))
Next varSelected
Me![txtAvgLicence] = dblLicenceFee / .ItemsSelected.Count
End If
End With
1
End Sub


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Hi all.

This code:

Private Sub cboNamen_AfterUpdate()

Dim intRowCount As Integer
Dim dblLicenceFee As Double
Dim intSelectCount As Integer

dblLicenceFee = 0#
intSelectCount = 0

For intRowCount = 0 To Me![cboNamen].Recordset.RecordCount - 1
If (Me![cboNamen].Selected(intRowCount) = True) Then
dblLicenceFee = dblLicenceFee + CDbl(Me![cboNamen].Column(2,
intRowCount))
intSelectCount = intSelectCount + 1
End If
Next intRowCount

If (intSelectCount = 0) Then
MsgBox "No licence selected!", vbInformation
Else
Me![txtAvgLicence] = dblLicenceFee / intSelectCount
End If

End Sub

I put in the event you can see of a multi selectable combobox
(Access
2007).
The code is OK, all records are filled, but in certain specific
circumstances (I know exactly when) I get an 'Invalid use of Null'
error
in
the line that adds the LicenceFee. But when I go to error correction
and
press F5, the code continues and completes without any error.
I tried requerying the control, build in a loop (in case of a timing
issue),
using other events, but I cannot get it fixed.
I feel it might be a bug in Access. I have created a specific
database
to
check the behavior. How can I get it to someone to confirm the
behavior
and
maybe get it to Microsoft?

Thanks,

Ronald.



.


.
 
D

Dirk Goldgar

Douglas J. Steele said:
Just to be certain. You're calling this "a multi selectable combobox", but
there's no such thing. Combo boxes do not have a MultiSelect property:
only list boxes do. Is this a combo box?


Since this is Access 2007, maybe the combo box is bound to a mult-value
field.
 
R

Ronald

True, not the combobox itself is multi selectable.
The control source has been made multi selectable.
Table design - specific field - tab LookUp:
Control: Combobox
Rowsource: the right table
Allow multiple values: Yes
(I hope that's te correct text, have to translate it from Dutch).
To be honest, I didn't know this, but the person who came to me for help did.

When in form design, you draw the field in Add ... fields (Ribbon left to
Properties) to the form, automatically a combobox is added.

Still, the control is a combobox and I should not get the 'Invalid use of
Null' error.


Douglas J. Steele said:
Just to be certain. You're calling this "a multi selectable combobox", but
there's no such thing. Combo boxes do not have a MultiSelect property: only
list boxes do. Is this a combo box?


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Ronald said:
I meant that the addition is not performed because the code immediately
jumps
from the 'For Each ...' line to the 'Me![txtAvgLicence] = ...' line. So
the
result always is 0.

I'm very sure column 2 is the right column. I checked it in immediate
mode.
Column 0 is the checkbox of the multi select combobox and column 1 is the
name of the licencee.

The table in the rowsource of the combobox contains 5 records.

I also tried:
Dim ctlControl as ComboBox

Set ctlCombobox = Me![cboNamen]
With [ctlCombobox]
and so on but it makes no difference.

Douglas J. Steele said:
Not sure what you mean by "no average is calculated"

Are you sure that the value you need to be averaging is the third column
of
your list box? (remember that the Column collection starts numbering at
0)

Are you sure that you've got the ColumnCount property of the list box set
to
at least 3?

Are you sure you've got all of the periods in there correctly? Without
the
With structure, the code would be

Private Sub cboNamen_AfterUpdate()

Dim dblLicenceFee As Double
Dim varSelected As Variant

dblLicenceFee = 0#

If Me![cboNamen].ItemsSelected.Count = 0 Then
MsgBox "No licence selected!", vbInformation
Else
For Each varSelected In Me![cboNamen].ItemsSelected
dblLicenceFee = dblLicenceFee + _
CDbl(Nz(Me![cboNamen].Column(2, varSelected), 0))
Next varSelected
Me![txtAvgLicence] = _
dblLicenceFee / Me![cboNamen].ItemsSelected.Count
End If

End Sub


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Hi Douglas.

Thanks for your code! Any enhancements are always appreciated!
But it does not function correctly, the result is always 0.
In immediate mode the .ItemsSelected.Count does display the correct
number
of items selected. But after the For Each line is processed the code
immediately goes to the 'Me![txtAvgLicence] = dblLicenceFee /
.ItemsSelected.Count' line, so no average is calculated.

Also my initial question still stands. Why do I get an 'Invalid use of
Null'
error while the table does not contain any empty fields? You use the Nz
function to trap the error but then you only get a wrong answer and
don't
get
an indication anything is wrong.
Why when I press F5 (or F8) after the 'Invalid use of Null' error
occurs,
code continues without any error! If there really is a Null value the
error
should reappear!
I have a database dedicated to this error to prove it.

Any additional help or suggestion is very welcome.

Ronald.


:

The code's ok, but it could be better:

Private Sub cboNamen_AfterUpdate()

Dim dblLicenceFee As Double
Dim varSelected As Variant

dblLicenceFee = 0#

With Me![cboNamen]
If .ItemsSelected.Count = 0 Then
MsgBox "No licence selected!", vbInformation
Else
For Each varSelected In .ItemsSelected
dblLicenceFee = dblLicenceFee + CDbl(Nz(.Column(2,
varSelected),
0))
Next varSelected
Me![txtAvgLicence] = dblLicenceFee / .ItemsSelected.Count
End If
End With
1
End Sub


--
Doug Steele, Microsoft Access MVP
http://www.AccessMVP.com/DJSteele
(no e-mails, please!)

Hi all.

This code:

Private Sub cboNamen_AfterUpdate()

Dim intRowCount As Integer
Dim dblLicenceFee As Double
Dim intSelectCount As Integer

dblLicenceFee = 0#
intSelectCount = 0

For intRowCount = 0 To Me![cboNamen].Recordset.RecordCount - 1
If (Me![cboNamen].Selected(intRowCount) = True) Then
dblLicenceFee = dblLicenceFee + CDbl(Me![cboNamen].Column(2,
intRowCount))
intSelectCount = intSelectCount + 1
End If
Next intRowCount

If (intSelectCount = 0) Then
MsgBox "No licence selected!", vbInformation
Else
Me![txtAvgLicence] = dblLicenceFee / intSelectCount
End If

End Sub

I put in the event you can see of a multi selectable combobox
(Access
2007).
The code is OK, all records are filled, but in certain specific
circumstances (I know exactly when) I get an 'Invalid use of Null'
error
in
the line that adds the LicenceFee. But when I go to error correction
and
press F5, the code continues and completes without any error.
I tried requerying the control, build in a loop (in case of a timing
issue),
using other events, but I cannot get it fixed.
I feel it might be a bug in Access. I have created a specific
database
to
check the behavior. How can I get it to someone to confirm the
behavior
and
maybe get it to Microsoft?

Thanks,

Ronald.



.



.


.
 

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