D
Derek
Hello -
I am working on an Excel chart with both a primary and secondary y-axis and
only one x-axis. The primary has positive and negative values. The
secondary has all positive values. I am using the secondary as a rank (by
selecting the box to invert values so the highest rank has a value of 1 and
appears at the top of the secondary y-axis, where rank 25 is the lowest
possible rank and appears at the bottom of the secondary y-axis), in theory
where the x and y axes meet. The x-axis is different points in time. So
this chart shows trends over time.
The issue I am having is the primary x-axis crosses the primary y-axis at 0
(y-axis value), which is what I want. However, the primary x-axis crosses
the secondary y-axis at a value that is not the lowest value on the secondary
y-axis. In this case, since I am using it as a rank, it is not crossing at
the lowest rank. I am not showing the secondary x-axis associated with rank.
I don't have this issue if all of the values on the primary y-axis are
positive. In other words, the primary x-axis crosses at 0 on the primary
y-axis and at the lowest rank on the secondary axis.
My question is, is there a way to fix my problem? Is there an option where
I can set the value where the primary x-axis crosses a value on the secondary
y-axis? I know I can set the value for Primary x-axis to primary y-axis -
and do the same for the secondary x and y axes, but I'm not aware of a way to
cross this primary - secondary boundary.
I imagine the graph's axes looking like a backwards 4 - the primary y-axis
goes above and below the primary x-axis. The primary x-axis is approximately
in the middle. The secondary y-axis is as high as the primary y-axis but
only goes down to the x-axis (i.e., it does not extend below the x-axis). Is
this possible?
Something like this:
| |
|_______|
|
|
Thanks!
- Derek
I am working on an Excel chart with both a primary and secondary y-axis and
only one x-axis. The primary has positive and negative values. The
secondary has all positive values. I am using the secondary as a rank (by
selecting the box to invert values so the highest rank has a value of 1 and
appears at the top of the secondary y-axis, where rank 25 is the lowest
possible rank and appears at the bottom of the secondary y-axis), in theory
where the x and y axes meet. The x-axis is different points in time. So
this chart shows trends over time.
The issue I am having is the primary x-axis crosses the primary y-axis at 0
(y-axis value), which is what I want. However, the primary x-axis crosses
the secondary y-axis at a value that is not the lowest value on the secondary
y-axis. In this case, since I am using it as a rank, it is not crossing at
the lowest rank. I am not showing the secondary x-axis associated with rank.
I don't have this issue if all of the values on the primary y-axis are
positive. In other words, the primary x-axis crosses at 0 on the primary
y-axis and at the lowest rank on the secondary axis.
My question is, is there a way to fix my problem? Is there an option where
I can set the value where the primary x-axis crosses a value on the secondary
y-axis? I know I can set the value for Primary x-axis to primary y-axis -
and do the same for the secondary x and y axes, but I'm not aware of a way to
cross this primary - secondary boundary.
I imagine the graph's axes looking like a backwards 4 - the primary y-axis
goes above and below the primary x-axis. The primary x-axis is approximately
in the middle. The secondary y-axis is as high as the primary y-axis but
only goes down to the x-axis (i.e., it does not extend below the x-axis). Is
this possible?
Something like this:
| |
|_______|
|
|
Thanks!
- Derek