Count to find the number of 100% 90% 80% in a column

[% Count]

I've tried different count functions but can't seem to get it right. I'm
trying to count the number of 100% on 1 line from a column on another sheet
and the 90%'s on another, 80% ..... The column I'm getting the 100% from is
a formula cell that returns this %. Could I please get help with this
formula.

 

[Max]

.. to count the number of 100%
Did you try something like this:
=COUNTIF(Sheet2!3:3,100%)
or
=COUNTIF(Sheet2!A:A,100%)

 

[T. Valko]

The column I'm getting the 100% from

is a formula cell that returns this %.

To count entries that equal 100%:

=COUNTIF(A1:A10,"100%")

Or:

=COUNTIF(A1:A10,1)

 

[% Count]

I've used the one with the 1 below and it return the 100% ok but I could not
get the 90%. I need to count the ones between 90 & 100 then 80 to 89 ect...
I'm not sure how to do that.

 

[T. Valko]

Follow this pattern:

100%:
=COUNTIF(A1:A10,100%)

90 to 99:
=COUNTIF(A1:A10,">=90%")-COUNTIF(A1:A10,">99%")

80 to 89:
=COUNTIF(A1:A10,">=80%")-COUNTIF(A1:A10,">89%")

70 to 79
=COUNTIF(A1:A10,">=70%")-COUNTIF(A1:A10,">79%")

etc
etc

 

[T. Valko]

P.S.

You might have to format the cells as GENERAL or NUMBER.

 

[% Count]

I tried this. I need to test more but it looks like it works?

=COUNTIF('Current '!I2:I9,">.89") - COUNTIF('Current '!I2:I9,">.99")

 

[T. Valko]

Yeah, that'll work. See my other reply.