counting consecutive absences

[jerry37917]

I have a worksheet that lists all the members of our church. Across the top
are all the Sundays in the year. Next to each person's name, I am filling
the sheet with either an A (Absent) or P (present). To the far left, I have
a column called "number of consecutive absences". What I need is a formula
to count the number of consecutive absences from the most reason Sunday.
Something like this:

John Smith A P A A P A A A 3

In the example John has missed three consecutive Sundays. If he is present
at the next meeting, the number would reset to 0. If he is absent, it would
then be 4. I don't need to count the total number of absences, just the
number of absences since the last attendance.

The purpose is to help our outreach teams keep in contact. When a person is
absent, we want to send a card, but when a person is absent twice in a row we
want to make a call...three times...a visit...and so on. This worksheet will
make it a lot easier to keep track of what the teams should be doing.

Thanks in advance for your help.

Jerry

 

[Bob Phillips]

Easily achieved with VBA. Assuming that the dates start in column C and the
absence count is in column B

Private Sub Worksheet_Change(ByVal Target As Range)
Dim i As Long
Dim nCount As Long
Dim nMax As Long

On Error GoTo ws_exit:
Application.EnableEvents = False
If Target.Column > 2 Then
With Target
For i = 3 To Me.Cells(1, Columns.Count).End(xlToLeft).Column
If Cells(.Row, i).Value = "a" Then
nCount = nCount + 1
Else
If nCount > nMax Then
nMax = nCount
End If
nCount = 0
End If
Next i
Me.Cells(.Row, "B").Value = nMax
End With
End If

ws_exit:
Application.EnableEvents = True
End Sub

'This is worksheet event code, which means that it needs to be
'placed in the appropriate worksheet code module, not a standard
'code module. To do this, right-click on the sheet tab, select
'the View Code option from the menu, and paste the code in.





--
HTH

Bob Phillips

(remove nothere from email address if mailing direct)

 

[Roger Govier]

Hi Jerry

You could do this with Conditional Formatting
Assuming your data starts in B2, then the earliest value that could have
three consecutive "A"'s is D2.
Also assuming you have 100 rows with data
Highlight D2:BB101
Format>Conditional Formatting>use dropdown to select Formual is and in
the whit epane type
=SUMPRODUCT(--(B22="A"))=3
Choose Format and select either a coloured Font or Red or Background of
Red
Click the Add button and repeat the above but set the last part of
formula =2, and a format of Yellow
Click Add button, change last part of formula to =1 and set Format to
Green

 

[jerry37917]

Thank you very much. Your code wasn't exactly what I was looking for, but it
gave me what I needed. I was able to modify it slighly and achieve the count
that I was wanting. I am relatively new to Excel and didn't even know this
was possible. Wow! I didn't realize just how powerful Excel really is.
Thanks again.

Jerry

 

[Bob Phillips]

That is just scratching the surface <bg>

--
HTH

Bob Phillips

(remove nothere from email address if mailing direct)

 

[Domenic]

Maybe...

=IF(COUNTIF(B1:BA1,"P"),COUNTIF(INDEX(B1:BA1,MATCH(2,1/(B1:BA1="P"))):BA1
,"A"),COUNTIF(B1:BA1,"A"))

....confirmed with CONTROL+SHIFT+ENTER, not just ENTER. Adjust the range
accordingly.

Hope this helps!

 

[StaceyJ]

Domenic,

I had a similar issue and just tried your solution. It worked perfect! I'm
trying to read through the function to try to understand what you actually
did. Haven't quite figured it out yet, but it works anyway!

Thanks again.