Take a look at the following:
Sub WordFrequency()
Dim SingleWord As String 'Raw word pulled from doc
Const maxwords = 9000 'Maximum unique words allowed
Dim Words(maxwords) As String 'Array to hold unique words
Dim Freq(maxwords) As Integer 'Frequency counter for Unique
Words
Dim WordNum As Integer 'Number of unique words
Dim ByFreq As Boolean 'Flag for sorting order
Dim ttlwds As Long 'Total words in the document
Dim Excludes As String 'Words to be excluded
Dim Found As Boolean 'Temporary flag
Dim j, k, l, Temp As Integer 'Temporary variables
Dim tword As String '
' Set up excluded words
' Excludes =
"[the][a][of][is][to][for][this][that][by][be][and][are]"
Excludes = ""
Excludes = InputBox$("Enter words that you wish to exclude,
surrounding each word with [ ].", "Excluded Words", "")
' Excludes = Excludes & InputBox$("The following words are
excluded: " & Excludes & ". Enter words that you wish to exclude,
surrounding each word with [ ].", "Excluded Words", "")
' Find out how to sort
ByFreq = True
Ans = InputBox$("Sort by WORD or by FREQ?", "Sort order", "FREQ")
If Ans = "" Then End
If UCase(Ans) = "WORD" Then
ByFreq = False
End If
Selection.HomeKey Unit:=wdStory
System.Cursor = wdCursorWait
WordNum = 0
ttlwds = ActiveDocument.Words.Count
Totalwords = ActiveDocument.Words.Count
' Control the repeat
For Each aword In ActiveDocument.Words
SingleWord = Trim(aword)
If SingleWord < "A" Or SingleWord > "z" Then SingleWord = ""
'Out of range?
If InStr(Excludes, "[" & SingleWord & "]") Then SingleWord =
"" 'On exclude list?
If Len(SingleWord) > 0 Then
Found = False
For j = 1 To WordNum
If Words(j) = SingleWord Then
Freq(j) = Freq(j) + 1
Found = True
Exit For
End If
Next j
If Not Found Then
WordNum = WordNum + 1
Words(WordNum) = SingleWord
Freq(WordNum) = 1
End If
If WordNum > maxwords - 1 Then
j = MsgBox("The maximum array size has been exceeded.
Increase maxwords.", vbOKOnly)
Exit For
End If
End If
ttlwds = ttlwds - 1
StatusBar = "Remaining: " & ttlwds & " Unique: " & WordNum
Next aword
' Now sort it into word order
For j = 1 To WordNum - 1
k = j
For l = j + 1 To WordNum
If (Not ByFreq And Words(l) < Words(k)) Or (ByFreq And
Freq(l) > Freq(k)) Then k = l
Next l
If k <> j Then
tword = Words(j)
Words(j) = Words(k)
Words(k) = tword
Temp = Freq(j)
Freq(j) = Freq(k)
Freq(k) = Temp
End If
StatusBar = "Sorting: " & WordNum - j
Next j
' Now write out the results
tmpName = ActiveDocument.AttachedTemplate.FullName
Documents.Add Template:=tmpName, NewTemplate:=False
Selection.ParagraphFormat.TabStops.ClearAll
With Selection
For j = 1 To WordNum
.TypeText Text:=Words(j) & vbTab & Trim(Str(Freq(j))) &
vbCrLf
Next j
End With
ActiveDocument.Range.Select
Selection.ConvertToTable
Selection.Collapse wdCollapseStart
ActiveDocument.Tables(1).Rows.Add BeforeRow:=Selection.Rows(1)
ActiveDocument.Tables(1).Cell(1, 1).Range.InsertBefore "Word"
ActiveDocument.Tables(1).Cell(1, 2).Range.InsertBefore
"Occurrences"
ActiveDocument.Tables(1).Range.ParagraphFormat.Alignment =
wdAlignParagraphCenter
ActiveDocument.Tables(1).Rows.Add
ActiveDocument.Tables(1).Cell(ActiveDocument.Tables(1).Rows.Count,
1).Range.InsertBefore "Total words in Document"
ActiveDocument.Tables(1).Cell(ActiveDocument.Tables(1).Rows.Count,
2).Range.InsertBefore Totalwords
ActiveDocument.Tables(1).Rows.Add
ActiveDocument.Tables(1).Cell(ActiveDocument.Tables(1).Rows.Count,
1).Range.InsertBefore "Number of different words in Document"
ActiveDocument.Tables(1).Cell(ActiveDocument.Tables(1).Rows.Count,
2).Range.InsertBefore Trim(Str(WordNum))
System.Cursor = wdCursorNormal
' j = MsgBox("There were " & Trim(Str(WordNum)) & " different words
", vbOKOnly, "Finished")
Selection.HomeKey wdStory
End Sub
--
Hope this helps.
Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.
Doug Robbins - Word MVP
Ian Bayly said:
Hi
I have an array of words.
I need to go through a large document and get a word count (case
insensitive) for each of the words in the array.
I thought the simplest way would be to do a .Find.Execute Replace: = <>
of each word and get the count of the replacements made.
I don't know how I get this count in VBA.
Can any one advise how I can get a count of the replacements, or suggest
another method.
Maybe I have to accept the time taken and do an iterative find.
TIA
Ian B
