counting x instances of a string across columns...

U

ucdcrush

A B C D
Yes No Yes Yes
No No No Yes
No Yes Yes No
Yes Yes No No


What I'm trying to do is count the cases where there is one "Yes" (or
maybe 2 or 3 yeses) in any of the columns, with one formula for the
entire array. So to count rows with one yes, there would be 1. With 3
yeses, there would be 1 row. With 2 yeses, there would be 2 rows.

Can't figure out how to do this without using a helper column, any
help is appreciated..
 
T

Toppers

Unless you have an overwhelming reason not to, I would use a helper column
using COUNTIF and then SUMIF/SUMPRODUCT to sum the results.
 
D

Dave Thomas

=SUM((A1="yes")+(B1="yes")+(C1="yes")+(D1="yes")) This produces the answer
3 for your first row.
=SUM((A2="yes")+(B2="yes")+(C2="yes")+(D2="yes")) This produces the answer
1 for your second row.
etc
Does this help?
 
D

Dave Thomas

=SUM((A1="yes")+(B1="yes")+(C1="yes")+(D1="yes")) This produces the answer
3 for your first row.
=SUM((A2="yes")+(B2="yes")+(C2="yes")+(D2="yes")) This produces the answer
1 for your second row.
etc
Does this help?
 
D

Dave Thomas

=SUM((A1="yes")+(B1="yes")+(C1="yes")+(D1="yes")) This produces the answer
3 for your first row.
=SUM((A2="yes")+(B2="yes")+(C2="yes")+(D2="yes")) This produces the answer
1 for your second row.
etc
Does this help?
 
T

T. Valko

Try this:

=SUMPRODUCT(--(MMULT(--(A1:D4="yes"),{1;1;1;1})=n))

Where n = 1, 2 or 3 (or whatever)

Note: this will work if you have no more than 5460 rows of data.
 
R

Ron Rosenfeld

A B C D
Yes No Yes Yes
No No No Yes
No Yes Yes No
Yes Yes No No


What I'm trying to do is count the cases where there is one "Yes" (or
maybe 2 or 3 yeses) in any of the columns, with one formula for the
entire array. So to count rows with one yes, there would be 1. With 3
yeses, there would be 1 row. With 2 yeses, there would be 2 rows.

Can't figure out how to do this without using a helper column, any
help is appreciated..


Given your data

Put the number of yes's per row in H1:Hn

Then **array-enter** this formula:

=SUM(--(MMULT(--($A$1:$D$4="Yes"),{1;1;1;1})=H1))

Copy/drag down.

To **array-enter**, hold down <ctrl><shift> while hitting <enter>. Excel will
place braces {...} around the formula.

The array constant should have the same number of "1's" as there are columns.
--ron
 
T

T. Valko

If you're going to go about it that way then you don't need the SUM
function.

As written, you're only summing a single number, the result of:

(A1="yes")+(B1="yes")+(C1="yes")+(D1="yes)

=SUM(3)

So, you can just use:

=(A1="yes")+(B1="yes")+(C1="yes")+(D1="yes")
 
T

T. Valko

Ron Rosenfeld said:
Given your data

Put the number of yes's per row in H1:Hn

Then **array-enter** this formula:

=SUM(--(MMULT(--($A$1:$D$4="Yes"),{1;1;1;1})=H1))

Copy/drag down.

To **array-enter**, hold down <ctrl><shift> while hitting <enter>. Excel
will
place braces {...} around the formula.

The array constant should have the same number of "1's" as there are
columns.
--ron

And, if you had 25 (or more) columns in your range you wouldn't necessarily
want to use:

{1;1;1;1;1;1;1;1;1;1;1;1;..............1}

You can generate that vertical array by adding this expression to the
formula:

TRANSPOSE(COLUMN(A1:D4)^0)

Note that TRANSPOSE is an array function and requires array entry. So in
using this you may as well use the SUM version rather than the SUMPRODUCT
version since *both* require array entry.

=SUM(--(MMULT(--(A1:D4="yes"),TRANSPOSE(COLUMN(A1:D4)^0))=n))
 
R

Ron Rosenfeld

Note that TRANSPOSE is an array function and requires array entry. So in
using this you may as well use the SUM version rather than the SUMPRODUCT
version since *both* require array entry.

=SUM(--(MMULT(--(A1:D4="yes"),TRANSPOSE(COLUMN(A1:D4)^0))=n))

I used the SUM function in my example.
--ron
 

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