Creating a regular six pointed star

[Peter Rooney]

Good afternoon, fellow Publishers!

This is probably a real no brainer, but what I'm trying to do is create a
six pointed star using basic shapes. I created an equilateral triangle (15cm
wide by 12.99cm high - basic trig using sin(60) to work out the height,
copied it and flipped the copy upside down. I then aligned the left edges of
the two stars...and this is where the problem started. No matter how far up
or down I move one triangle in relation to the other, it just doesn't LOOK
right.

I need some sort of formula to say "given the height of the triangle, how
many cm down from the y origin of the first triange does the second triange
have to be?"

Unless of course someone can advise me as to how to get a six pointed star
from some other version of "basic shapes". I inadvertantly posted this in
the Excel forum and someone helpfully advised me to create a regular hexagon
and extend the sides.

I'm going to give this a go, but in, in the meantime anyone has any other
ideas, I'm all ears!

I use 2003 at work and 2000 at home.

 

[Peter Rooney]

In relation to the other posting, does anyone know what the ratio of width to
height should be for hexagons to make them regular? For equilateral
traingles, if (for example) the width is 15, the height should be 12.99 - a
ratio of 1.154:1.

 

[Mary Sauer]

Create a triangle, start with these dimensions,Width 2.54cm Height 1.905cm,
copy/paste, slide the new triangle until the bottom corners meet, flip the second
vertical, copy/paste this triangle, flip vertical and so on...