Evaluating columns based on criteria

[mike.wilson8]

Can someone help with the code below and see what needs to be
changed/added? I'm getting an Object variable or With block variable
not set error on line - mycell_Fruit =
..Range(.cells(1,1),.cells(rows.count,1).End(xlup)). This code was
posted to me yesterday from (e-mail address removed).

Thank you


lastrow = Cells(Rows.Count, 3).End(xlUp).Row
Dim mycell_Fruit As Range
with Worksheets("sheet1")
mycell_Fruit = .Range(.cells(1,1),.cells(rows.count,1).End(xlup))
End with
For i = lastrow To 1 Step -1
bMatch = True
for j = 6 to 10
if not isempty(cells(i,j)) then
res = Application.Match(cells(i,j),mycell_Fruit,0)
if iserror(res) then
bMatch = False
exit for
end if
end if
next
if bMatch then cells(i,"E").value = "Fruit"
Next

 

[Don Guillett]

try

mycell_Fruit = .Range(.cells(1,1),.cells(rows.count,1).End(xlup))

mycell_Fruit = .Range(.cells(1,1),.cells(rows.count.End(xlup),1))

 

[Tom Ogilvy]

with Worksheets("sheet1")
set mycell_Fruit = .Range(.cells(1,1),.cells(rows.count,1).End(xlup))
End with

 

[mike.wilson8]

Thank you very much..it seems to be working like a charm. This code is
so quick and dirty vs. doing a long IF statement for each column. This
will be tucked away for future projects.

 

[Don Guillett]

mybad