Extracting charecter from a string

T

Trevor Aiston

I have strings of text which are file locations within a worksheet
e.g "\Clinical_Audit\Projects\Project Monitoring\Audit\0910\CAMHS\02
Improving access to appropriate services for children, young people and their
families\"
I want to extract the service code from the string (ins this case "CAMHS")
and can do for this row using
=MID(D3,56,5)
But some of the service directories (all begin at char 56) are the same
length (5) others have 4 char some 2 etc.

ANy ideas who to acheive this?

THanks
Trevor
 
J

Jarek Kujawa

do you wish to achieve this:

=MID(D3;FIND("0910\",D3)+5,LEN(D3)-FIND("0910\",D3)-5)

?
 
G

Gary''s Student

=LEFT(MID(A1,56,999),FIND("\",MID(A1,56,999))-1)

We get EVERYTHING from 56 to the end and then look for the first separator.
 
P

Pete_UK

Change your formula to this:

=MID(D3,56,FIND("\",D3,56)-56)

This looks for the next \ after the 56th character to determine how
many characters to extract.

Hope this helps.

Pete
 

Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments. After that, you can post your question and our members will help you out.

Ask a Question

Top