W
Walter Briscoe
I run Excel 2003.
In columns("G:H"), I have:
£8.00 £4.80
£8.00 -£0.90
£8.00 £2.70
I can identify that "-0.90" in VBA with
Dim Overcharge As String
Overcharge = Application.Min(Columns("G:H"))
I want to identify all the cells which have that value. My example shows
one, but there could be more.
In Excel itself, I can select columns G and H and do Edit/Find... or
Ctrl+F to get to the Find and Replace dialog, where I set Find What: to
£-0.90 and click "Find All" to get a list of matching cells.
When I record a macro doing this, it just records the selection.
Is there a method which would return an array of matches?
(I want to avoid the tedium of find and a findnext loop.)
P.S. in VBA, I can refer equivalently to columns("G") and columns(7).
I can also refer to columns("G:H").
Is there a numeric equivalent to columns("G:H")?
columns(7,8) does not work. ;(
I discount something like
dim maxrow as long
maxrow = application.max(cells(7,range(7,65536).end(xlUp).row, _
cells(8,range(8,65536).end(xlUp).row))
Range(cells(7,1), cells(8, maxrow))
I've just thrown that together and don't vouch for it doing as I intend.
In columns("G:H"), I have:
£8.00 £4.80
£8.00 -£0.90
£8.00 £2.70
I can identify that "-0.90" in VBA with
Dim Overcharge As String
Overcharge = Application.Min(Columns("G:H"))
I want to identify all the cells which have that value. My example shows
one, but there could be more.
In Excel itself, I can select columns G and H and do Edit/Find... or
Ctrl+F to get to the Find and Replace dialog, where I set Find What: to
£-0.90 and click "Find All" to get a list of matching cells.
When I record a macro doing this, it just records the selection.
Is there a method which would return an array of matches?
(I want to avoid the tedium of find and a findnext loop.)
P.S. in VBA, I can refer equivalently to columns("G") and columns(7).
I can also refer to columns("G:H").
Is there a numeric equivalent to columns("G:H")?
columns(7,8) does not work. ;(
I discount something like
dim maxrow as long
maxrow = application.max(cells(7,range(7,65536).end(xlUp).row, _
cells(8,range(8,65536).end(xlUp).row))
Range(cells(7,1), cells(8, maxrow))
I've just thrown that together and don't vouch for it doing as I intend.