G
Guest
Hi,
tried my best to find the answer through the HELP menu and
the knowlege base...but unsucessfull.
I have an expense tracking Excel file, with worksheets for
every months. Each worksheet has the same format.
Column A has a controlled list of expense type (Office
Supplies, Entertainment, Telehpone...etc). Column B has
the amount. Each row is an expense. Here is an example:
- Worksheet 1 (Jan 04)
COLUMN A COLUMN B
Telephone $245
Rent $500
Gaz $46
Office Exp. $456
- Worksheet 2 (Feb 04)
COLUMN A COLUMN B
Telephone $233
Rent $500
Gaz $12
etc....
I need to create a worksheet that resumes all the expenses
per category. That means that I need to write a formula
for each expense type that does the following, for
exmaple: Find in all the worksheets, in Column A a value
equal to "Telephone", get the value on the same row in
column B and calculate the total for this category only.
Therfore, on the first worksheet it will resume all my
expenses for year in each category.
I thank anyone in advance for his ingenious help !.
Regards.
tried my best to find the answer through the HELP menu and
the knowlege base...but unsucessfull.
I have an expense tracking Excel file, with worksheets for
every months. Each worksheet has the same format.
Column A has a controlled list of expense type (Office
Supplies, Entertainment, Telehpone...etc). Column B has
the amount. Each row is an expense. Here is an example:
- Worksheet 1 (Jan 04)
COLUMN A COLUMN B
Telephone $245
Rent $500
Gaz $46
Office Exp. $456
- Worksheet 2 (Feb 04)
COLUMN A COLUMN B
Telephone $233
Rent $500
Gaz $12
etc....
I need to create a worksheet that resumes all the expenses
per category. That means that I need to write a formula
for each expense type that does the following, for
exmaple: Find in all the worksheets, in Column A a value
equal to "Telephone", get the value on the same row in
column B and calculate the total for this category only.
Therfore, on the first worksheet it will resume all my
expenses for year in each category.
I thank anyone in advance for his ingenious help !.
Regards.