Getting Access filename only in 97

M

MarkCapo

Using Access XP you call the currentproject method and
pick up its name property to return the filename of the
current application file. I need to to a similar
function in 97 which only picks up the filename directly
rather than using a procedure that loops through the path
and filename to pick out filename from the
application.name result.

Can anybody help with this!

Thanks

mark
 

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