J
Joe Leon
I have a form that
On Open I have the following Event Procedure to open as blank.
Private Sub Form_Open(Cancel As Integer)
DoCmd.OpenForm "tblPick_Eq"
DoCmd.GoToRecord , , acNewRec
End Sub
In the form I created a button to "Copy to New Record"
On Click I have the following Even Procedure
Private Sub CopyRecord_Click()
On Error GoTo Err_CopyRecord_Click
DoCmd.DoMenuItem acFormBar, acEditMenu, 8, , acMenuVer70
DoCmd.DoMenuItem acFormBar, acEditMenu, 2, , acMenuVer70
DoCmd.DoMenuItem acFormBar, acEditMenu, 5, , acMenuVer70 'Paste Append
Exit_CopyRecord_Click:
DoCmd.GoToRecord acForm, Me.Name, acNewRec 'goes to new record
Exit Sub
Err_CopyRecord_Click:
MsgBox Err.Description
Resume Exit_CopyRecord_Click
What I want to happen is that the new record is displayed. Instead what is
happening is that a blank record is displayed. I did noticed that the
duplicate record is getting done because if I go back one record from the
blank record the data is there.
How do I fix this?
Thanks! Joe....
On Open I have the following Event Procedure to open as blank.
Private Sub Form_Open(Cancel As Integer)
DoCmd.OpenForm "tblPick_Eq"
DoCmd.GoToRecord , , acNewRec
End Sub
In the form I created a button to "Copy to New Record"
On Click I have the following Even Procedure
Private Sub CopyRecord_Click()
On Error GoTo Err_CopyRecord_Click
DoCmd.DoMenuItem acFormBar, acEditMenu, 8, , acMenuVer70
DoCmd.DoMenuItem acFormBar, acEditMenu, 2, , acMenuVer70
DoCmd.DoMenuItem acFormBar, acEditMenu, 5, , acMenuVer70 'Paste Append
Exit_CopyRecord_Click:
DoCmd.GoToRecord acForm, Me.Name, acNewRec 'goes to new record
Exit Sub
Err_CopyRecord_Click:
MsgBox Err.Description
Resume Exit_CopyRecord_Click
What I want to happen is that the new record is displayed. Instead what is
happening is that a blank record is displayed. I did noticed that the
duplicate record is getting done because if I go back one record from the
blank record the data is there.
How do I fix this?
Thanks! Joe....