J
Jorge Cervantes
I received this email f rom China. It appears to be from a scammer in
Beijing.
I would like to find the sender's original IP address.
The copy of the internet header for the email message (received in
Outlook07) is as follows.
There are five "received from" lines. I am wondering which one is to use
idetify the sender's IP address..
I am using Outlook 2007 and Windows 7. Jorge
***************************
Return-path: <[email protected]>
Envelope-to: aaa@bbbb
Delivery-date: Tue, 20 Apr 2010 22:31:48 -0400
Received: from impinc01.yourhostingaccount.com ([10.1.13.101]
helo=impinc01.yourhostingaccount.com)
by mailscan14.yourhostingaccount.com with esmtp (Exim)
id 1O4PjA-0006US-6Z
for aaaa@bbbb; Tue, 20 Apr 2010 22:31:48 -0400
Received: from mail.idcsea.com ([220.231.142.1])
by impinc01.yourhostingaccount.com with NO UCE
id 82Xk1e03Y0211rQ022XlE7; Tue, 20 Apr 2010 22:31:48 -0400
X-EN-OrigIP: 220.231.142.1
X-EN-IMPSID: 82Xk1e03Y0211rQ022XlE7
Received: from localhost (localhost.localdomain [127.0.0.1])
by mail.idcsea.com (EMOS V1.5 (Postfix)) with ESMTP id A7A1628ECBE;
Wed, 21 Apr 2010 10:31:39 +0800 (CST)
X-DSPAM-Result: Whitelisted
X-DSPAM-Processed: Wed Apr 21 10:31:39 2010
X-DSPAM-Confidence: 0.9997
X-DSPAM-Probability: 0.0000
X-DSPAM-Signature: 1,4bce638b295361083620689
X-Virus-Scanned: amavisd-new at idcsea.com
Received: from mail.idcsea.com ([127.0.0.1])
by localhost (mail.idcsea.com [127.0.0.1]) (amavisd-new, port 10024)
with ESMTP id o7Gu5VkI8d5o; Wed, 21 Apr 2010 10:31:38 +0800 (CST)
Received: from 20100321-1337 (unknown [222.72.137.103])
by mail.idcsea.com (EMOS V1.5 (Postfix)) with ESMTPA id E078328F42F;
Wed, 21 Apr 2010 10:12:53 +0800 (CST)
Reply-To: (e-mail address removed)
From: "abcde"<[email protected]>
To:
Subject:
=?GB2312?B?QW5ub3VuY2VtZW50LVRoZSBicmFuZCChsCBpbnNpdHVzobEgZGlzcHV0ZS4=?=
Date: Wed, 21 Apr 2010 10:14:20 +0800
Message-Id: <[email protected]>
MIME-Version: 1.0
Content-Type: multipart/related;
boundary="----=_NextPart_10042110034467168632145_001"
X-Priority: 1
X-Mailer: DreamMail 4.4.1.0
Beijing.
I would like to find the sender's original IP address.
The copy of the internet header for the email message (received in
Outlook07) is as follows.
There are five "received from" lines. I am wondering which one is to use
idetify the sender's IP address..
I am using Outlook 2007 and Windows 7. Jorge
***************************
Return-path: <[email protected]>
Envelope-to: aaa@bbbb
Delivery-date: Tue, 20 Apr 2010 22:31:48 -0400
Received: from impinc01.yourhostingaccount.com ([10.1.13.101]
helo=impinc01.yourhostingaccount.com)
by mailscan14.yourhostingaccount.com with esmtp (Exim)
id 1O4PjA-0006US-6Z
for aaaa@bbbb; Tue, 20 Apr 2010 22:31:48 -0400
Received: from mail.idcsea.com ([220.231.142.1])
by impinc01.yourhostingaccount.com with NO UCE
id 82Xk1e03Y0211rQ022XlE7; Tue, 20 Apr 2010 22:31:48 -0400
X-EN-OrigIP: 220.231.142.1
X-EN-IMPSID: 82Xk1e03Y0211rQ022XlE7
Received: from localhost (localhost.localdomain [127.0.0.1])
by mail.idcsea.com (EMOS V1.5 (Postfix)) with ESMTP id A7A1628ECBE;
Wed, 21 Apr 2010 10:31:39 +0800 (CST)
X-DSPAM-Result: Whitelisted
X-DSPAM-Processed: Wed Apr 21 10:31:39 2010
X-DSPAM-Confidence: 0.9997
X-DSPAM-Probability: 0.0000
X-DSPAM-Signature: 1,4bce638b295361083620689
X-Virus-Scanned: amavisd-new at idcsea.com
Received: from mail.idcsea.com ([127.0.0.1])
by localhost (mail.idcsea.com [127.0.0.1]) (amavisd-new, port 10024)
with ESMTP id o7Gu5VkI8d5o; Wed, 21 Apr 2010 10:31:38 +0800 (CST)
Received: from 20100321-1337 (unknown [222.72.137.103])
by mail.idcsea.com (EMOS V1.5 (Postfix)) with ESMTPA id E078328F42F;
Wed, 21 Apr 2010 10:12:53 +0800 (CST)
Reply-To: (e-mail address removed)
From: "abcde"<[email protected]>
To:
Subject:
=?GB2312?B?QW5ub3VuY2VtZW50LVRoZSBicmFuZCChsCBpbnNpdHVzobEgZGlzcHV0ZS4=?=
Date: Wed, 21 Apr 2010 10:14:20 +0800
Message-Id: <[email protected]>
MIME-Version: 1.0
Content-Type: multipart/related;
boundary="----=_NextPart_10042110034467168632145_001"
X-Priority: 1
X-Mailer: DreamMail 4.4.1.0