I have two columns 1 & 0 and want to choose those cell with 1 by .

[Dr. saeed mohtasham nia]

Dear friends: I have two set of data only 1 & 0. and want to use countif
function
to choose those cells with only 1.
my data is here:
1 0
0 1
1 1
0 1
1 0
1 1

I want to count the cells containing only 1 1
please helpme. thanks.

 

[Ragdyer]

Try this:

=SUMPRODUCT((A1:A6=1)*(B1:B6=1))

 

[WLMPilot]

This can be done two ways since you are dealing with 1's and 0's. I assume
you have two columns with these numbers in them. I will use Columns A & B
and Rows 1-6

1st Way: =COUNTIF(A1:B6,"=1")

2nd Way: Since you are looking for all the 1's, you could also SUM them and
get the same answer: =SUM(A1:B6)

 

[JMB]

If the data is only 1's and 0's:
=SUMPRODUCT(A1:A6, B1:B6)

 

[Bob Phillips]

or even =COUNTIF(A1:B6,1)

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[RagDyeR]

Some interpretation needed here!

OP's next to last line reads:

<<<"I want to count the cells containing only 1 1 ">>>

Which I *and* JMB take to mean "matching pairs of columns".

With JMB's formula being more concise then my suggestion, until I checked,
It really bothered me that a Countif would *also* perform to *my*
interpretation of the question.

Glad to see that it was your understanding of the problem and not my
ineptitude, where I couldn't recognize a Countif solution as opposed to a
Sumproduct solution.<vbg>

You do that to me quite often, where I'm ready to post a suggestion, but you
beat me to it, with a more fitting solution, making me glad that I'm not as
fast as you.

Didn't you mention somewhere that you have files (solutions) saved, where
you just "copy & post"?<bg>

--

Regards,

RD
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or even =COUNTIF(A1:B6,1)

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[Bob Phillips]

Yeah, but not COUNTIF Rick, those tend to be VBA snippets, more complex
arrays, or verbose wordy explanations.

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

 

[Ragdyer]

So ... what you're actually (politely) saying is ... You *are* faster!<bg>

 

[Bob Phillips]

It's all timing Rick. Sometimes I am on the NGs and a question pops up,
sometimes elsewhere. Many times you, Biff, Norman Jones, Tom, Dave P et al
beat me too it, but I still like to read the responses, there is always
something to learn. I think it was Ardus that accused me of being the
fastest fingers West of Colorado, seeing as I am about 4,500 miles east of
there, I think he was a bit off

Bob

 

[JMB]

fastest fingers West of Colorado, seeing as I am about 4,500 miles east of

there, I think he was a bit off

That just means Far West of Colorado.

 

[Bob Phillips]

I guess you are right, keep forgetting the world is round <G>

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)