R
Rufus V. Smith
Is there a function to extract the URL part of a hyperlink in another cell?
All I can see is the displayed text for the link.
if I use, for example, =A1 in another cell, all I get is a
copy of the displayed text.
What I am trying to do is automatically create a column of proper urls,
given a list
behind "displayed" urls.
Rufus
All I can see is the displayed text for the link.
if I use, for example, =A1 in another cell, all I get is a
copy of the displayed text.
What I am trying to do is automatically create a column of proper urls,
given a list
behind "displayed" urls.
Rufus