Lookup based on reference

[Doug]

The other day, I used this formula to lookup table data based on the row and
column such as
=INDEX($R$3:$AA$41,MATCH(FLOOR($S$1,0.1),$Q$3:$Q$41,1),MATCH(FLOOR($S$1-FLOOR($S$1,0.1),0.01),$R$2:$AA$2,0))

So that If I had the number 2.22, it will return for me .15 from the table
lookup table (made up values)
.00 .01 .02 .03 .04 ... .09
2.0 .31 .32 .33 .34 .35 ... .50
2.1 .21 .35 .51 .51 .25 ... .85
2.2 .53 .52 .15 .52 .51 ... .81
2.3 .89 .58 .23 .45 .15 ... .15

My question now is, based on the above formula, how would I be able to do
the opposite. So if I have the indexed value; say .15, and I want it to
return 2.22?

 

[AB]

How the formula is supposed to know whether the .15 'means' 2.22 or
2.39 (as they both would return .15)?

 

[Bernard Liengme]

I think we need more. Suppose the know value was 0.51 (which occurs more
than once), would you want 2.1 or 2.2 returned?
best wishes

 

[Jacob Skaria]

Array entered with query value in cell T1

=INDEX(Q:Q,MIN(IF($R$3:$AA$41=T1,ROW($R$3:$AA$41))))+
INDEX(2:2,MIN(IF($R$3:$AA$41=T1,COLUMN($R$3:$AA$41))))

 

[Doug]

I am sorry, let me give more detail.
These are the actual values in a portion of the table; If cell "T1" says
".12" I need it to first recognize the closest value, being between 0.1179 &
0.1217. Second since it is closer to 0.1217 it would return the value ".31".
How can this be accomplished please?

0.00 (0.01) 0.02 0.03
0.0 0.0000 0.0040 0.0080 0.0120
0.1 0.0398 0.0438 0.0478 0.0517
0.2 0.0793 0.0832 0.0871 0.0910
(0.3) 0.1179 (0.1217) 0.1255 0.1293
0.4 0.1554 0.1591 0.1628 0.1664
0.5 0.1915 0.1950 0.1985 0.2019
0.6 0.2257 0.2291 0.2324 0.2357
0.7 0.2580 0.2611 0.2642 0.2673
0.8 0.2881 0.2910 0.2939 0.2967
0.9 0.3159 0.3186 0.3212 0.3238
1.0 0.3413 0.3438 0.3461 0.3485
1.1 0.3643 0.3665 0.3686 0.3708

 

[Bernard Liengme]

Doug,
You still have not given us the complete picture
The number that is closest to 0.21 is 0.2019 in the 0.4 column of the 0.5
row
How are we to know which row or column to search?
best wishes