macro to bold number of chars from end of a string

[herbwarri0r]

Hi all, (first time I've used a forum such as this)

I have a work book that produces a two page document by using
concatenate and information entered on the first worksheet. What I need
to do is make a number of chars in a string bold. I can't use;

With ActiveCell.Characters(Start:=118, Length:=8).Font
..Name = "Arial"
..FontStyle = "Bold"
..Size = 12

As there is a varying length to the string due to the company name
being cancatenated in. Tried changing start to end but this did not
work. The characters I need bold are dates and will also be the only
numbers in the string.

I've also tried recording a macro to create the formula =RIGHT(B46,60)
to get the start of the text I need bold, paste it into a new cell and
format the needed chars to bold. Then all I need to do in insert the
test before in in that cell so to keep the formatting. This works but
the recoded macro uses the string of text when I need it to use the
cell reference for the company name.


=CONCATENATE("In the event of ",'Control Sheet'!E5,"'s"," failure to
remedy the Payment Breach We will refuse to accept any new orders for
the Service and/or suspend access to the Gateway on
",TEXT(Calender!AB5,"dd/mm/yyyy")," and/or exercise its right to
terminate the Contract and the Service provided under it at 12:00 on
",TEXT(Calender!AD5,"dd/mm/yyyy"),".")

So to surmise I need to paste the above to a new worksheet as values
and make the dates bold, but because the value in 'Control Sheet'!E5 is
going to be of a varying length I'm having trouble.

 

[robert111]

if cell A1 contains the text string "bob 18/1/06 fred 24/1/06 dick" you
can search for a number between 0 and 9 , this will return the position
of the various numbers within the string. Use the lowest number.
LEN(A1) will give you the string length, can you work with this?

 

[herbwarri0r]

if cell A1 contains the text string "bob 18/1/06 fred 24/1/06 dick"
you
can search for a number between 0 and 9 , this will return the
position
of the various numbers within the string. Use the lowest number.
LEN(A1) will give you the string length, can you work with this?


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Still a bit unsure of how I can do this in a macro. I can use;

ActiveCell = Application.SEARCH(0,ActiveCell,1)
ActiveCell = Application.SEARCH(1,ActiveCell,1)
ActiveCell = Application.SEARCH(2,ActiveCell,1)
ActiveCell = Application.SEARCH(3,ActiveCell,1) ....etc

But then how do I use the lowest number and use this to be the value of
Start in the following?

With ActiveCell.Characters(Start:=118, Length:=8).Font
..Name = "Arial"
..FontStyle = "Bold"
..Size = 12

I also have the problem that each of my text strings has two dates
through the data. So the above method would be fine to make the first
date bold but I will have trouble making the second date bold. I
suppose there must be a way as each date uses 8 characters. So the
second date will have a start point of the ninth lowest value returned
from using Application.Search.

 

[Dave Peterson]

In your original post, you used a format of dd/mm/yyyy. In this example, you
lost the leading 0's in the day and only used two digit years.

This will work if you really use a format of dd/mm/yyyy. (But remember, you
have to be formatting values--not formulas--formulas can't use this kind of
character by character formatting.)

Option Explicit
Sub testme()
Dim myRng As Range
Dim myCell As Range
Dim iCtr As Long

Set myRng = Nothing
On Error Resume Next
Set myRng = Intersect(Selection, _
Selection.Cells.SpecialCells(xlCellTypeConstants, xlTextValues))

On Error GoTo 0

If myRng Is Nothing Then
MsgBox "No constants"
Exit Sub
End If

For Each myCell In myRng.Cells
For iCtr = 1 To Len(myCell.Value)
If Mid(myCell.Value, iCtr, 10) Like "##/##/####" Then
With myCell.Characters(Start:=iCtr, Length:=10).Font
.Name = "Arial"
.Bold = True
.Size = 12
End With
End If
Next iCtr
Next myCell
End Sub

 

[herbwarri0r]

In your original post, you used a format of dd/mm/yyyy. In this
example, you
lost the leading 0's in the day and only used two digit years.

This will work if you really use a format of dd/mm/yyyy. (But
remember, you
have to be formatting values--not formulas--formulas can't use this
kind of
character by character formatting.)

Option Explicit
Sub testme()
Dim myRng As Range
Dim myCell As Range
Dim iCtr As Long

Set myRng = Nothing
On Error Resume Next
Set myRng = Intersect(Selection, _
Selection.Cells.SpecialCells(xlCellTypeConstants, xlTextValues))

On Error GoTo 0

If myRng Is Nothing Then
MsgBox "No constants"
Exit Sub
End If

For Each myCell In myRng.Cells
For iCtr = 1 To Len(myCell.Value)
If Mid(myCell.Value, iCtr, 10) Like "##/##/####" Then
With myCell.Characters(Start:=iCtr, Length:=10).Font
.Name = "Arial"
.Bold = True
.Size = 12
End With
End If
Next iCtr
Next myCell
End Sub
Dave Peterson

Thanks a lot! That worked brilliantly. Much appreaciated.