need help on MAX

[Malik Nadeem]

need your assitance on this below fomula i have question on
formula i.e. =MAX((C4-D4) + MAX(C4-2*D4,0) + 2*MAX(C4-3*D4,0),0)*E4*80
now i want to change this formula but when i m changing the value after E4
its will not giving me the correct result OR not working properly

now my question is like this
charges per day of 1 LAP is 160 (from day 1st to 5th day) in above formula 80
2nd LAP is per day 320 (from day 6th to 10th days) in above formula 160
3rd slap is per day 640 ( from day 11 to ownworld for example 999) in .... 320

when i m using below it is not working
=MAX((C4-D4) + MAX(C4-2*D4,0) + 2*MAX(C4-3*D4,0),0)*E4*160

A4=10-JAN-2009
B4=28-JAN-2009
C4=19
D4=4
E4=1
F4=should be 5600 instead of 6400
total C4 is 19 days D4 is free days Left which is not visible i.e. 15 days
now we charge this 1st 5 days 5x160 2ndl lap from 6-10 days which equal to
320 per days and rest multiply with 640

remarks Note:
if d4 is grater then or equal to 5 its is working properly.
if d4 value is less then 5 its not giving correct value .
can you please guide how can i cahnge this one

thanks in advnace for support and help.

regards
Malik Nadeem

 

[Bob Phillips]

=SUMPRODUCT(--((C4-D4)>{0,5,10}), ((C4-D4)-{0,5,10}), {160,160,320})

 

[Bernard Liengme]

Could you please explain what the formula should do.

This is what is does now
=MAX((C4-D4) + MAX(C4-2*D4,0) + 2*MAX(C4-3*D4,0),0)*E4*160
=MAX( 15 + MAX(C4-2*D4,0) + 2*MAX(C4-3*D4,0),0)*E4*160
=MAX( 15 + 11 + 2*MAX(C4-3*D4,0),0)*E4*160
=MAX( 15 + 11 + 14,0)*E4*160
=MAX(40,0)*E4*160
=40*1*160 = 6400

How do you get 5600?

 

[JE McGimpsey]

See a reply in the previous thread.

Please don't post the same question under two separate threads - first,
it tends to fragment any answers you get, but it also wastes the time of
those responding to a previously answered question.

 

[Bernard Liengme]

Bob,
I am very impressed that you could see this answers from the OP's question!
Must be the UK beer that keeps the mind so alert!

 

[Bob Phillips]

It keeps us something Bernard, but I can't remember what ...

 

[Malik Nadeem]

Dear Bob Phillips

thanks for your below help kindly further advise can i convert last
"{160,160,320}" into a "{C6,C6,C8}"?

example
=SUMPRODUCT(--((C4-D4)>{0,5,10}), ((C4-D4)-{0,5,10}), {160,160,320})
=SUMPRODUCT(--((C4-D4)>{0,5,10}), ((C4-D4)-{0,5,10}), {C6,C6,C8})

when the value of C6=80 & c8=160

waiting for your usual support.

=+++++++++++++++++++++++++++++++++

 

[Bernard Liengme]

No, that will not work but this will:
=SUMPRODUCT(--((C4-D4)>{0,5,10}), ((C4-D4)-{0,5,10}), C6:E6)
Note the use of a HORIZONTAL range of THREE cells (any such range will work)
You will fill these with 160, 160, 320 for your purpose
If you must use a vertical range, then try replacing the comma with the
braces by semi-colons
=SUMPRODUCT(--((C4-D4)>{0;5;10}), ((C4-D4)-{0;5;10}), C6:C8)

best wishes

 

[Malik Nadeem]

{"Bernard Liengme" wrote====> =MAX((C4-D4)
it should be 19 instead of 15
beacuse C4=19 & D4=4
any how solved with the help of sumproduct formula
thanks bop

 

[Malik Nadeem]

revised with corrected value of C6 & C8
sorry for inconvenience

 

[Malik Nadeem]

yes its working good i need this result its great but i want to do some
little more changes in the cell C7

i want to only show value in C7=320 instead of C7=160
C6:c8 mean 160, 160, 640
when i putting in a c7=320 result change which is not correct for me
example
if
C4=7
D4=0
C6=160
C7=160
C8=640
=SUMPRODUCT(--((C4-D4)>{0;5;10}), ((C4-D4)-{0;5;10}), B6:B8)
result=1440 correct 100% correct answer

but i need like this
C4=1
D4=0
C6=160
C7=320
C8=640
=SUMPRODUCT(--((C4-D4)>{0;5;10}), ((C4-D4)-{0;5;10}), B6:B8)
result=1760 (wrong for me i want 1440)

is there any posiblity

kindly advise

 

[Bob Phillips]

This will work, put 0 in B5 and use

=SUMPRODUCT(--((C4-D4)>{0;5;10}), ((C4-D4)-{0;5;10}),ABS((B6:B8)-(B5:B7)))

 

[Malik Nadeem]

okay thanks bob

This will work, put 0 in B5 and use

=SUMPRODUCT(--((C4-D4)>{0;5;10}), ((C4-D4)-{0;5;10}),ABS((B6:B8)-(B5:B7)))

--
__________________________________
HTH

Bob