Next without For..?

[merry_fay]

Hi,

I've written this bit of basic code to hide some rows for me:

Sub hiddenrow()

Range("A1").Select

For i = 1 To 516
ActiveCell.Offset(1, 0).Select
If ActiveCell.Value = "hiddenrow" Then
Selection.EntireRow.Hidden = True
Else

Next i

End Sub

but when I try to run it it, it comes up with the Compile Error 'Next
without For'
I've used For & I can't see what I've done wrong! Can anyone help please?

Thanks
merry_fay

 

[Jacob Skaria]

Every IF statement would need a End If Statement which is missing in your
code..

Sub hiddenrow()

Range("A1").Select

For i = 1 To 516
ActiveCell.Offset(1, 0).Select
If ActiveCell.Value = "hiddenrow" Then
Selection.EntireRow.Hidden = True
Else
'somthing
End If
Next i

End Sub

 

[Jarek Kujawa]

insert "End If" instead of "Else"

 

[RonaldoOneNil]

Change Else to End if

 

[merry_fay]

Thankyou -I must have beeen having a really blond 5 mins!!

 

[Dana DeLouis]

Thankyou -I must have beeen having a really blond 5 mins!!

Just an idea...

Sub hiddenrow()
Dim R As Long
Const s As String = "hiddenrow"

For R = 1 To 516
Rows(R).Hidden = Cells(R, 1).Value = s
Next R
End Sub

HTH
Dana DeLouis