Numbers Not Calculating Correct on Userform

[RyanH]

I have a Userform with 4 Textboxes labeled Height(Ft), Height(Ins),
Width(Ft), and Width(Ins). I have a Label Caption that I use to combine the
results of what was entered in the 4 textboxes when I click a command button.
For some reason when I enter 1 in the Width(Ins) Textbox the label will show
1.0625" instead of 1".

Public Sub Preview()

Dim height As Double
Dim width As Double
Dim Hft As Double
Dim Hins As Double
Dim Wft As Double
Dim Wins As Double
Dim Face As String

'result of which face was selected on userform
If optSingleFace = True Then
Face = optSingleFace.Caption
Else
Face = optDoubleFace.Caption
End If

height = Val(tbxHeightFt) + Val(tbxHeightIns) / 12 'face height in ft
MsgBox height
width = Val(tbxWidthFt) + Val(tbxWidthIns) / 12 'face width in ft
MsgBox width

'dimensions of cabinet in feet & inches
Hft = Int(height)
MsgBox Hft
Hins = WorksheetFunction.Ceiling((height - Hft) * 12, 0.0625)
MsgBox Hins
Wft = Int(width)
MsgBox Wft
Wins = WorksheetFunction.Ceiling((width - Wft) * 12, 0.0625)
MsgBox (Wins)

'Preview Line 1: Single/Double Face, Extruded Cabinet: Dimensions
lblPreview1.Caption = Face & ", Extruded Cabinet: " & Hft & "'-" & Hins
& "'' H x " & Wft & "'-" & Wins & "'' W x " & Val(tbxDepthIns) & "'' D"

End Sub

Thanks, Ryan

 

[Ronald R. Dodge, Jr.]

Are you attempting to show this in inches or in feet? Your statement says
one thing, and the code shows another. Also, when you got the result, did
you have a "1" in the Width(Ft) text box?

 

[RyanH]

width should be calculated in feet.
Yes, I had a 1 in the WidthFT textbox.

For some reason when I enter a 1 in the WidthFT textbox and 1 in the
widthIns textbox my label shows 1 ft and 1.0625 inches. It should say 1 ft 1
inch. Why is this happening?

Thanks
Ryan

 

[Ronald R. Dodge, Jr.]

The only place where the 1/16 would come from would be either if you are
measuring in fractions of an inch or it's from "16 ounces = 1 pound". .0625
= 1/16. I never really knew about the CEILING function until now, but with
what I see how it's used, I could only think of limited cases to use it such
as in carpentry where you would measure in 16ths and you wouldn't want to
cut boards too short, so rounding up to the next 16ths in such a case would
make sense.

If you want to have it show as "1 ft 1 inch", then use the following:

MsgBox tbxWidthFt & " ft " & tbxWidthIns & " inch", vbOK

If you want to have it show as "1.0833 ft", then use the following

width = Val(tbxWidthFt) + Int(Val(tbxWidthIns) / 12*10000)/10000 'face
width in ft
MsgBox CStr(width) & " ft", vbOK

Note, multiplications and divisions takes precedence over additions and
subtractions

If you have a decimal form number and you need to take it to the "# ft #
inch" format going to the nearest inch, then use the following:

MsgBox Int(width) & " ft " & Int((width - Int(width))*12+0.5) & " inch"

Sincerely,

Ronald R. Dodge, Jr.
Production Statistician
Master MOUS 2000

 

[Mark Lincoln]

This may be a situation where your code actually produces a number
just slightly greater than 1, (1.00000003, say) which CEILING then
rounds to 1.0625 as instructed. That's a problem sometimes with
representing decimal numbers in binary. You may want to round to the
nearest .0625 inch as opposed to rounding up to the next .0625 in. as
CEILING does. Conversely, you may want to subtract a very small
fraction from the number you're processing with CEILING in order to
try to counteract the problem.

Mark Lincoln

 

[RyanH]

We build outdoor signs here so we would like to round up to the nearest 1/16
of an inch. I would like my code to be "universal" so my users can enter the
length in decimal format or foot & inch format. For example, the user will
enter 5.5 in the HeightFt textbox and the code returns 5 ft - 6 inches or the
user will enter 5 in the HeightFt textbox and 6 in the HeightIns textbox and
the code returns 5 ft - 6 inches.

Here is a simpler form of code of what I am trying to do. For some reason
Hins and Wins do NOT equal when I enter the same number in tbxHeightIns and
tbxWidthIns. Such as .125 or .0625.

Private Sub cmbEstimate_Click()

Dim Lheight As Double
Dim Lwidth As Double
Dim Hft As Double
Dim Hins As Double
Dim Wft As Double
Dim Wins As Double

Lheight = Val(tbxHeightFt) + Val(tbxHeightIns) / 12 'face height in ft
'MsgBox Lheight
Lwidth = Val(tbxWidthFt) + Val(tbxWidthIns) / 12 'face width in ft
'MsgBox Lwidth

'dimensions of cabinet in feet & inches
Hft = Int(Lheight)
MsgBox Hft
Hins = WorksheetFunction.Ceiling((Lheight - Hft) * 12, 0.0625)
MsgBox Hins
Wft = Int(Lwidth)
MsgBox Wft
Wins = WorksheetFunction.Ceiling((Lwidth - Wft) * 12, 0.0625)
MsgBox (Wins)

End Sub

Thanks,
Ryan

 

[RyanH]

I'll just use a factor = -0.000001. That works beautifully, Thanks.

 

[RyanH]

I got it to work now. This is what I did.

Public Sub Preview()

Dim height As Single
Dim width As Single
Dim Hft As Byte
Dim Hins As Single
Dim Wft As Byte
Dim Wins As Single
Dim Face As String

'result of which face was selected on userform
If optSingleFace = True Then
Face = optSingleFace.Caption
Else
Face = optDoubleFace.Caption
End If

'round height & width to the nearest 1/16th of an inch
height = Round(Val(tbxHeightFt) * 12 * 16 + Val(tbxHeightIns) * 16)
'height in 1/16th of inches
width = Round(Val(tbxWidthFt) * 12 * 16 + Val(tbxWidthIns) * 16)
'width in 1/16th of inches

'dimensions of cabinet in feet & inches
Hft = Int(height / 16 / 12)
Hins = (Round((height / 16 / 12 - Hft) * 12 * 16)) / 16
Wft = Int(width / 16 / 12)
Wins = (Round((width / 16 / 12 - Wft) * 12 * 16)) / 16

'Preview Line 1: Single/Double Face, Extruded Cabinet: Dimensions
lblPreview1.Caption = Face & ", Extruded Cabinet: " & Hft & "'-" & Hins
& "'' H x " & Wft & "'-" & Wins & "'' W x " & Val(tbxDepthIns) & "'' D"

End Sub

Thanks,
Ryan