J
J.Allman
SO I want my team managers to easily identify tasks that are running behind
that CAN be corrected and completed before BASELINE finish of the task in
question. The idea is that at the most a resource can work an additional 2
hours per day to make up the variance. What I am trying to identify is the
number of hours remaining in the work to complete the task that is running
behind and divide that number by the number of days I have left from [current
date] until I hit the baseline finish for that task.
In the formula below:
1= between .1 and 2 hours of overtime per day = achievable
3 = above 2 hours of overtime per pay = doubtful
8 = the formula returns a calculation of 0 or negative which means that the
current date has already passed the baseline finish or is the same day as the
baseline finish and thus no amount of overtime can get the task to finish by
baseline finish = impossible
IIf(([Work]-[Actual Work])/([Baseline Finish]-[Current
Date])>2,3,IIf(([Work]-[Actual Work])/([Baseline Finish]-[Current
Date])>0,1,IIf(([Work]-[Actual Work])/([Baseline Finish]-[Current
Date])<=0,8)))
So far I cant get the formula to work properly. I am guessing because I am
really bad at coding my formulas..if I had to guess the logic is good but I
am missing something like [Minutes Per Day] in the formula.
Can I get some help?
I also just realized I probably need to add something to the front of this
formula to exclude any tasks that have been completed so I can avoid running
into a numerator = 0 in my formula and thus get an "ERROR" or something.
that CAN be corrected and completed before BASELINE finish of the task in
question. The idea is that at the most a resource can work an additional 2
hours per day to make up the variance. What I am trying to identify is the
number of hours remaining in the work to complete the task that is running
behind and divide that number by the number of days I have left from [current
date] until I hit the baseline finish for that task.
In the formula below:
1= between .1 and 2 hours of overtime per day = achievable
3 = above 2 hours of overtime per pay = doubtful
8 = the formula returns a calculation of 0 or negative which means that the
current date has already passed the baseline finish or is the same day as the
baseline finish and thus no amount of overtime can get the task to finish by
baseline finish = impossible
IIf(([Work]-[Actual Work])/([Baseline Finish]-[Current
Date])>2,3,IIf(([Work]-[Actual Work])/([Baseline Finish]-[Current
Date])>0,1,IIf(([Work]-[Actual Work])/([Baseline Finish]-[Current
Date])<=0,8)))
So far I cant get the formula to work properly. I am guessing because I am
really bad at coding my formulas..if I had to guess the logic is good but I
am missing something like [Minutes Per Day] in the formula.
Can I get some help?
I also just realized I probably need to add something to the front of this
formula to exclude any tasks that have been completed so I can avoid running
into a numerator = 0 in my formula and thus get an "ERROR" or something.