D
Dan Pickard
Hi,
I am re-creating an Approach database in Access and I am having problems
with my relationships. In Approach the Join that is created is ; -
Insert - "If no records match the "Otherset" record, typing into a blank
"Locations" field inserts a new record.
Insert - "If no records match the "Location" record, typing into a blank
"Otherset" field inserts a new record.
The relationship is created on the ID fields of both tables but when I am
trying to replicate this in Access I end up with the ID numbers being shown
for the "Otherset" table so lots of duplicate numbers and not the ID numbers
for the "Locations" table as I wanted.
I thought the relationship in Access was a one to many (one being
"Location", many being "otherset") with a Join Property of option 2 (include
ALL records from 'tblLocation' and only those records from 'tblOtherset'
where the joined fields are equal). But obviously I am mistaken.
Any advice or ideas would be greatly appreciated.
--
Dan Pickard
-----------------------------
Powerful Windows 2003 web hosting, design and training.
http://www.hosting.fast-trak.net
http://www.design.fast-trak.net
http://www.training.fast-trak.net
http://www.fast-trak.net
I am re-creating an Approach database in Access and I am having problems
with my relationships. In Approach the Join that is created is ; -
Insert - "If no records match the "Otherset" record, typing into a blank
"Locations" field inserts a new record.
Insert - "If no records match the "Location" record, typing into a blank
"Otherset" field inserts a new record.
The relationship is created on the ID fields of both tables but when I am
trying to replicate this in Access I end up with the ID numbers being shown
for the "Otherset" table so lots of duplicate numbers and not the ID numbers
for the "Locations" table as I wanted.
I thought the relationship in Access was a one to many (one being
"Location", many being "otherset") with a Join Property of option 2 (include
ALL records from 'tblLocation' and only those records from 'tblOtherset'
where the joined fields are equal). But obviously I am mistaken.
Any advice or ideas would be greatly appreciated.
--
Dan Pickard
-----------------------------
Powerful Windows 2003 web hosting, design and training.
http://www.hosting.fast-trak.net
http://www.design.fast-trak.net
http://www.training.fast-trak.net
http://www.fast-trak.net