selecting CurrentRecord in a subform

[Allen_N]

I want to advance the current record in a subform (in DataSheet view) when
the user clicks a button on the parent form. The name of the subform control
is "subfrmKitsFound2". If I use:

DoCmd.GoToRecord acDataForm, "subfrmKitsFound2", acNext

I just get the error:

The object 'subfrmKitsFound2' isn't open.

I get the same error if I instead use the name of the form upon which the
subform is based ("Kits Found subform sp").

Am I trying to do something that is unsupported by Access 2003?

 

[George Nicholson]

Subforms aren't considered to be open Forms, so you can't use GoToRecord,
which needs the name of an open form.

From the subform:
Me.Recordset.MoveNext

From the parent form (replacing NameOfSubFormControl with the name of the
Control, not the Form):
Me.NameOfSubformControl.Form.Recordset.MoveNext

HTH,

 

[Marshall Barton]

I want to advance the current record in a subform (in DataSheet view) when
the user clicks a button on the parent form. The name of the subform control
is "subfrmKitsFound2". If I use:

DoCmd.GoToRecord acDataForm, "subfrmKitsFound2", acNext

I just get the error:

The object 'subfrmKitsFound2' isn't open.

I get the same error if I instead use the name of the form upon which the
subform is based ("Kits Found subform sp").

Try this:

With Me.subfrmKitsFound2.Form.Recordset
If .AbsolutePostition < .RecordCount - 1 Then
.MoveNext
Else
'already at last record, what to do??
End If
End With

 

[Allen_N]

Thanks George,

I thought it would be something like that.