Starting Access application with a batch file.

[TADropik]

My Access application is split in to 2 mdb's, a client interface and the data.

The client interface resides on the local computer and the data resides on
the server.

I often update the client interface and put the new version on the server
along side the data.

The user then executes a batch file that copies the client interface to the
local and opens it from there.

The problem with useing a batch file is it keeps the Cmd.exe window open
even after the Access mdb is open.

Is there a better way to do this so an extra window doesn't remain open?

 

[Dirk Goldgar]

My Access application is split in to 2 mdb's, a client interface and the
data.

The client interface resides on the local computer and the data resides on
the server.

I often update the client interface and put the new version on the server
along side the data.

The user then executes a batch file that copies the client interface to
the
local and opens it from there.

The problem with useing a batch file is it keeps the Cmd.exe window open
even after the Access mdb is open.

Is there a better way to do this so an extra window doesn't remain open?

How are you starting the database from the batch file? I just tested this
in a batch file:

start /D "C:\Users\Dirk\Documents" test.mdb

and the command window closed after the database was loaded.

 

[TADropik]

I see now that it was my lack of experience with Batch Files.
That did it Dirk.

Thank you.