J
Jeff
Hi All
I am trying to write a query that will tell me how many unique activities a
rep has made and I am having some problems - here is the situation:
I have a table that stores activities from my sales reps
The table has these fields:
CampaignRecordID
BillToNum
ShipToNum
ContactNum
The reps add activities to a campaign record or to a client in our
database - the record in the Activity table stores all of the information
and all of the activities the reps make
I can write a query that will tell me how many activities a rep made each
day
But I am trying to write a query that will tell me how many activities they
made to Unique contacts each day - so if they made 5 activities to the same
CampaignRecordID or same BillTo I only want to count that as one.
I guess I am either trying to suppress duplicates if that is possible or
write some other type of query that will allow me to include only unique
contact.
I am not sure if I have expressed myself enough here - please let me know if
you need any more information and thanks in advance for anyone's assistance
with this.
Jeff
I am trying to write a query that will tell me how many unique activities a
rep has made and I am having some problems - here is the situation:
I have a table that stores activities from my sales reps
The table has these fields:
CampaignRecordID
BillToNum
ShipToNum
ContactNum
The reps add activities to a campaign record or to a client in our
database - the record in the Activity table stores all of the information
and all of the activities the reps make
I can write a query that will tell me how many activities a rep made each
day
But I am trying to write a query that will tell me how many activities they
made to Unique contacts each day - so if they made 5 activities to the same
CampaignRecordID or same BillTo I only want to count that as one.
I guess I am either trying to suppress duplicates if that is possible or
write some other type of query that will allow me to include only unique
contact.
I am not sure if I have expressed myself enough here - please let me know if
you need any more information and thanks in advance for anyone's assistance
with this.
Jeff