user form check box vba

[emmy128]

Hi I am working on a user form that pops up when the spreadsheet is open,
allowing the user to enter all the entries they need to. Each entry is
automatically entered one below the other... now, i'd like to have a place on
my user form that allows the user to select checkboxes, then have a
corresponding cell display the word "yes" if its checked, and to remain blank
if its not.

how in the heck to i program this... ? my text boxes are all programmed like
this:

LastRow.Offset(1, 0).Value = TextBox1.Text
LastRow.Offset(1, 2).Value = TextBox2.Text
LastRow.Offset(1, 3).Value = TextBox3.Text
LastRow.Offset(1, 4).Value = TextBox4.Text
LastRow.Offset(1, 5).Value = TextBox5.Text

and my combo boxes are like this:

If ComboBox1.Value <> "" Then _
LastRow.Offset(1, 7).Value = ComboBox1.Value


i will have 4 check boxes, that will correspond to columns 8, 9, 10, 11

hope this helps!

Thank you in advance!

Em~

 

[Corey]

If CheckBox1 = True Then 'True is when the CheckBox is Ticked.
'Place here what you want to happen If the CheckBox IS Ticked.

Hi I am working on a user form that pops up when the spreadsheet is open,
allowing the user to enter all the entries they need to. Each entry is
automatically entered one below the other... now, i'd like to have a place on
my user form that allows the user to select checkboxes, then have a
corresponding cell display the word "yes" if its checked, and to remain blank
if its not.

how in the heck to i program this... ? my text boxes are all programmed like
this:

LastRow.Offset(1, 0).Value = TextBox1.Text
LastRow.Offset(1, 2).Value = TextBox2.Text
LastRow.Offset(1, 3).Value = TextBox3.Text
LastRow.Offset(1, 4).Value = TextBox4.Text
LastRow.Offset(1, 5).Value = TextBox5.Text

and my combo boxes are like this:

If ComboBox1.Value <> "" Then _
LastRow.Offset(1, 7).Value = ComboBox1.Value


i will have 4 check boxes, that will correspond to columns 8, 9, 10, 11

hope this helps!

Thank you in advance!

Em~

 

[Bob Phillips]

or even

If Checkbox1 Then
...

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HTH

Bob

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